![]() ![]() ![]() ![]() just results for personID = 10 I need both totalPoints and rank overall and filtered by date. One option is to use a ranking variable, such as the following: SELECT firstname, age, gender, curRank : curRank + 1 AS rank FROM person p, (SELECT curRank : 0) r ORDER BY age The (SELECT curRank : 0) part allows the variable initialization without requiring a separate SET command. If it's easier, I ultimately need to display in my application the totalPoints and rank for 1 person (to be supplied by PHP) i.e. Ideal Result only February messages: personID | totalPoints | rank So, given the following query: SELECT CASE WHEN prev x.cityid THEN a WHEN prev : x.cityid THEN a : a + 1 END rank FROM (SELECT prev : NULL, a : 0) y, ( SELECT FROM sakila.address a ORDER BY a. If the above output is possible, I'm wondering if it is possible to produce the same output with a date range filter such as only messages from the month of February. Ideal Result: personID | totalPoints | rank Messages Table example messageID | personID | dateOfMessage | messagePoints Kamil Bladoszewski sql learn sql rank online practice Don’t struggle with SQL ranking functions anymore This article will guide you through the most common ranking use cases. I'm sure there is a way to do this entirely with a query but I don't have a clue where to start. Then store the result in PHP and order the result by totalPoints. SELECT SUM(messagePoints) AS totalPoints FROM Messages I am wondering if there is a query that would sum up all the points per person and order them by rank?Ĭurrently the only way I know how to get the output I'm looking for is to run this: I have a mySQL database table I'm using to store messages sent out to people. MySQL 8.0 introduces a rank () function that adds some additional functionality for ranking records in a result set. ![]()
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